How to Know whether an Ion Will Form an Inner Orbital Complex or an Outer Orbital Complex

Is it necessary that a strong-field ligand (SFL) causes electron-pairing?


Spectrochemical series (in the increasing order of the ligand-field strength):

I− < Br− < S2− < SCN− < Cl− < NO3− < N3− < F− < OH− < C2O42− < O2− < H2O < NCS− < CH3CN < EDTA4- < py < NH3 < en < bipy < phen < NO2− < PPh3 < CN− < CO

py = Pyridine, en = Ethylenediamine, bipy = 2,2'-Bipyridine, phen = 1,10-Phenanthroline, PPh3 = Triphenylphosphine

Mnemonic: I Bring Some Sweet Chocolate Nice Nuts For Our Cute Optimistic Happy Naughty Children Effortlessly, Perhaps Not Enough, But Pal, No Problem Caring Cubs

Question:

Which of the following ions will form an inner orbital complex? Which one(s) will form an outer orbital complex?

[Co(NH3)6]3+, [Ni(NH3)6]2+, [Ni(H2O)6]2+

Solution infographics:





Click/tap to enlarge the images

WFL = Weak-field ligand, CN = Coordination number

Does it look interesting❓ Let Chemaficionado know in the comments below or at mychemistryhomework@gmail.com❗

References:

(1)    Spectrochemical series. Wikipedia. https://en.wikipedia.org/wiki/Spectrochemical_series.

(2)    Wikipedia Contributors. Orbital hybridisation. Wikipedia. https://en.wikipedia.org/wiki/Orbital_hybridisation.‌

(3) Mnemonic: Modified (by Chemaficionado) internet source

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